题解:【ICPC WF 2021 G】 Mosaic Browsing

· · 题解

劲爆的阅读体验

题目链接

数据有点水啊,貌似矩阵大小最大只有 500,这导致一堆 bitset 乱搞或者暴力啥的无聊解法能过,这里就不多说了,快进到正题。

二维通配符匹配。

首先根据 Rabin Karp 给每种颜色随机一个权值做哈希,特别的,令通配符(也就是 0)的权值为 0。下文称模式串为 A,匹配串为 B。接下来要做的就是设计匹配函数和卷积。

将两个矩阵拍到一维上,套路性的翻转 A 矩阵后相乘。这里有一个小技巧,为了使 AB 能够对应上位置,我们在 A 的前 r_p - 1 行末尾补 0,补到长度为 c_q。具体的,可以有例子:

\begin{aligned} & c_q = 4,A = \begin{bmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ \end{bmatrix} \\ & \sf A = \begin{bmatrix} 1 & 2 & 3 & 0 & 4 & 5 & 6 \end{bmatrix} \\ & \sf A' = \begin{bmatrix} 6 & 5 & 4 & 0 & 3 & 2 & 1 \end{bmatrix} \\ & A' = \begin{bmatrix} 6 & 5 & 4 \\ 3 & 2 & 1 \\ \end{bmatrix} \\ \end{aligned}

注意到这样就实现了 A_{i,j}' = A_{r_p - i + 1,c_p - j + 1}。此时我们要求匹配函数:

\begin{aligned} P_{x,y} &= \sum_{1 \leq i < r_p} \sum_{1 \leq j < c_p} A_{i,j} B_{x + i - 1,y + i - 1} \\ &= \sum_{1 \leq i < r_p} \sum_{1 \leq j < c_p} A_{r_p - i + 1,c_p - i + 1}' B_{x + i - 1,y + i - 1} \end{aligned}

注意到下标里的东西加起来正好是 (x + r_p,y + c_p),然后就可以愉快的卷积求 P 了。

K = \sum_{i = 1}^{r_p} \sum_{j = 1}^{c_p} A_{i,j}^2,注意到匹配串中不存在通配符,模式串中的通配符 0 不管遇到什么颜色乘出来这一位都是 0,能与 K 中所算的一项对应起来。所以如果存在 P_{x,y} = K,则说明在 B_{x,y} 这个位置匹配上了。注意最后统计答案的时候再判一下位置是否合法就好了,这是简单的。综上我们做到了 \mathcal O(T \log T),其中 T = (r_p + r_q)(c_p + c_q)。个人采用了 NTT 实现,再不要脸的推一波我的多项式板子,跑的非常优秀。

#include<bits/stdc++.h>
#define ld long double
#define ui unsigned int
#define ull unsigned long long
#define int long long
#define eb emplace_back
#define pb pop_back
#define ins insert
#define mp make_pair
#define pii pair<int,int>
#define fi first
#define se second
#define power(x) ((x)*(x))
#define gcd(x,y) (__gcd((x),(y)))
#define lcm(x,y) ((x)*(y)/gcd((x),(y)))
#define lg(x,y)  (__lg((x),(y)))
#define y1 LJBL
using namespace std;

namespace FastIO
{
    template<typename T=int> inline T read()
    {
        T s=0,w=1; char c=getchar();
        while(!isdigit(c)) {if(c=='-') w=-1; c=getchar();}
        while(isdigit(c)) s=(s*10)+(c^48),c=getchar();
        return s*w;
    }
    template<typename T> inline void read(T &s)
    {
        s=0; int w=1; char c=getchar();
        while(!isdigit(c)) {if(c=='-') w=-1; c=getchar();}
        while(isdigit(c)) s=(s*10)+(c^48),c=getchar();
        s=s*w;
    }
    template<typename T,typename... Args> inline void read(T &x,Args &...args)
    {
        read(x),read(args...);
    }
    template<typename T> inline void write(T x,char ch)
    {
        if(x<0) x=-x,putchar('-');
        static char stk[25]; int top=0;
        do {stk[top++]=x%10+'0',x/=10;} while(x);
        while(top) putchar(stk[--top]);
        if(ch!='~') putchar(ch);
        return;
    }
}
using namespace FastIO;

inline void file()
{
    freopen(".in","r",stdin);
    freopen(".out","w",stdout);
    return;
}

bool Mbe;

namespace LgxTpre
{
    static const int MAX=4000010;
    static const int inf=2147483647;
    static const int INF=4557430888798830399;
    static const int mod=1e9+7;
    static const int bas=131;

    namespace Poly
    {
        namespace MInt
        {
            static const int Mod=998244353;
            template<const int Mod> struct ModInt
            {
                int x;
                ModInt(int X=0):x(X) {}
                inline ModInt operator = (int &T) {*this.x=T; return *this;}
                inline ModInt operator = (const ModInt &T) {this->x=T.x; return *this;}
                inline friend ModInt operator + (ModInt a,ModInt b) {return a.x+b.x>=Mod?a.x+b.x-Mod:a.x+b.x;}
                inline friend ModInt operator - (ModInt a,ModInt b) {return a.x-b.x<0?a.x-b.x+Mod:a.x-b.x;}
                inline friend ModInt operator * (ModInt a,ModInt b) {return a.x*b.x%Mod;}
                inline friend ModInt operator ^ (ModInt a,int b) {ModInt res=1; while(b) {if(b&1) res=res*a; a=a*a; b>>=1;} return res;}
                inline friend ModInt operator / (ModInt a,ModInt b) {return a*(b^(Mod-2));}
                inline ModInt operator += (const ModInt &T) {*this=*this+T; return *this;}
                inline ModInt operator -= (const ModInt &T) {*this=*this-T; return *this;}
                inline ModInt operator *= (const ModInt &T) {*this=*this*T; return *this;}
                inline ModInt operator ^= (const ModInt &T) {*this=*this^T; return *this;}
                inline ModInt operator /= (const ModInt &T) {*this=*this/T; return *this;}
                template<typename T> inline friend ModInt operator + (ModInt a,T x) {return a+ModInt(x);}
                template<typename T> inline friend ModInt operator - (ModInt a,T x) {return a-ModInt(x);}
                template<typename T> inline friend ModInt operator * (ModInt a,T x) {return a*ModInt(x);}
                template<typename T> inline friend ModInt operator / (ModInt a,T x) {return a/ModInt(x);}
                inline friend bool operator == (ModInt a,ModInt b) {return a.x==b.x;}
                inline friend bool operator != (ModInt a,ModInt b) {return a.x!=b.x;}
                inline friend bool operator >  (ModInt a,ModInt b) {return a.x>b.x;}
                inline friend bool operator <  (ModInt a,ModInt b) {return a.x<b.x;}
                inline friend bool operator >= (ModInt a,ModInt b) {return a>b||a==b;}
                inline friend bool operator <= (ModInt a,ModInt b) {return a<b||a==b;}
                template<typename T> inline friend bool operator == (ModInt a,T b) {return a==ModInt(b);}
                template<typename T> inline friend bool operator != (ModInt a,T b) {return a!=ModInt(b);}
                template<typename T> inline friend bool operator >  (ModInt a,T b) {return a>ModInt(b);}
                template<typename T> inline friend bool operator <  (ModInt a,T b) {return a<ModInt(b);}
                template<typename T> inline friend bool operator >= (ModInt a,T b) {return a>=ModInt(b);}
                template<typename T> inline friend bool operator <= (ModInt a,T b) {return a<=ModInt(b);}
                inline bool operator ! () {return !x;}
                inline ModInt operator - () {return x?Mod-x:0;}
            };
        }
        using namespace MInt;
        static const ModInt<Mod> gn=332748118,gni=3,ZERO=0,ONE=1;
        struct poly
        {
            vector<ModInt<Mod>> a;
            inline ModInt<Mod> &operator [] (int i) {return a[i];}
            inline poly operator = (const poly &T) {this->a=T.a; return *this;}
            inline int size()         {return a.size();}
            inline ModInt<Mod> back() {return a.back();}
            inline void resize(int N) {return a.resize(N),void();}
            inline void reverse()     {return std::reverse(a.begin(),a.end());}
            inline void pin(int x)    {return a.emplace_back(ModInt<Mod>(x)),void();}
            inline void pout()        {for(auto it:a) write(it.x,' ');}
        };
        static const int GT=21,GR=31;
        ModInt<Mod> omega[MAX]; poly zero,one;
        inline int Sup(int N) {int K=1; while(K<N) K<<=1; return K;}
        inline void Prework(int N)
        {
            zero.a.emplace_back(ZERO),one.a.emplace_back(ONE);
            int K=1; while((1<<K)<N) ++K; K=min(K-1,21ll);
            omega[0]=1,omega[1<<K]=(ModInt<Mod>(GR))^(1<<(GT-K));
            for(int i=K;i>=1;--i) omega[1<<(i-1)]=omega[1<<i]*omega[1<<i];
            for(int i=1;i<(1<<K);++i) omega[i]=omega[i&(i-1)]*omega[i&(-i)];
        }
        inline void NTT(poly &F,int typ)
        {
            ModInt<Mod> U,V;
            int N=F.size();
            if(typ==1)
            {
                for(int mid=N>>1;mid>=1;mid>>=1)
                    for(int i=0,k=0;i<N;i+=mid<<1,++k)
                        for(int j=0;j<mid;++j)
                            U=F[i+j],V=F[i+j+mid]*omega[k],
                            F[i+j]=U+V,F[i+j+mid]=U-V;
            }
            if(typ==-1)
            {
                for(int mid=1;mid<N;mid<<=1)
                    for(int i=0,k=0;i<N;i+=mid<<1,++k)
                        for(int j=0;j<mid;++j)
                            U=F[i+j],V=F[i+j+mid],
                            F[i+j]=U+V,F[i+j+mid]=(U-V)*omega[k];
                ModInt<Mod> Ninv=ONE/N;
                for(int i=0;i<N;++i) F[i]*=Ninv;
                reverse(F.a.begin()+1,F.a.end());
            }
        }
        inline poly operator * (poly a,poly b)
        {
            int K=a.size()+b.size()-1,N=Sup(K);
            a.resize(N),b.resize(N);
            NTT(a,1),NTT(b,1);
            for(int i=0;i<N;++i) a[i]*=b[i];
            NTT(a,-1);
            a.resize(K);
            return a;
        }
    }
    using namespace Poly;

    int rp,cp,rq,cq;
    int tag[MAX],cnt=1;

    inline void lmy_forever()
    {
        Poly::Prework(4000000);

        read(rp,cp); vector a(rp,vector<int>(cp));
        for(int i=0;i<rp;++i) for(int j=0;j<cp;++j) read(a[i][j]);
        read(rq,cq); vector b(rq,vector<int>(cq));
        for(int i=0;i<rq;++i) for(int j=0;j<cq;++j) read(b[i][j]);

        auto random=[&](int l,int r)->int
        {
            static mt19937_64 sd(20070707);
            static uniform_int_distribution<int> range(l,r);
            return range(sd);
        };

        for(int i=1;i<=rq*cq;++i) tag[i]=1;
        vector<int> col(110);
        for(int i=1;i<=100;++i) col[i]=random(1,Mod-1);
        poly A,B,C; ModInt<Mod> tmp;
        for(int i=0;i<rp;++i) {int j=0; for(;j<cp;++j) A.pin(col[a[i][j]]),tmp+=A.back()*A.back(); if(i<rp-1) for(;j<cq;++j) A.pin(0);}
        for(int i=0;i<rq;++i) for(int j=0;j<cq;++j) B.pin(col[b[i][j]]);
        A.reverse(),C=A*B;
        for(int i=0;i<B.size()-A.size()+1;++i) if(C[A.size()+i-1]!=tmp) tag[i+1]=0;
        vector<pii> ans;
        for(int i=1;i<=rq;++i) for(int j=1;j<=cq;++j,++cnt) if(i+rp-1<=rq&&j+cp-1<=cq&&tag[cnt]) ans.eb(mp(i,j));
        write(ans.size(),'\n');
        for(auto [x,y]:ans) write(x,' '),write(y,'\n');
        return;
    }
}

bool Med;

signed main()
{
//  file();
    fprintf(stderr,"%.3lf MB\n",abs(&Med-&Mbe)/1048576.0);
    int Tbe=clock();
    LgxTpre::lmy_forever();
    int Ted=clock();
    cerr<<1e3*(Ted-Tbe)/CLOCKS_PER_SEC<<" ms\n";
    return (0-0);
}