题解 P5712 【【深基3.例4】Apples】
题目传送门
思路
-
仔细读题后,我们可以发现,输出可以分成
2 种情况,apple加s与apple不加s,所以我们可以使用if/else来实现。 -
接着,我们读入
n。int n; cin>>n; -
进行判断,是否需要加
sif(n==1 || n==0) cout<<"Today, I ate "<<n<<" apple."; else cout<<"Today, I ate "<<n<<" apples.";
参考代码
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin>>n;
if(n==1 || n==0) cout<<"Today, I ate "<<n<<" apple.";
else cout<<"Today, I ate "<<n<<" apples.";
return 0;
}