B3823题解
不开 long long 见祖宗。
思路:
营业时间
营业时间
用成本
代码部分:
#include <bits/stdc++.h>
using namespace std;
long long a, b, k, r, c;
long long ying, cheng, xiao, li;
int main() {
cin>> a >> b >> k >> r >> c;
ying = b - a;
cheng = ying * k * c;
xiao = ying * k * r;
li = xiao - cheng;
cout << li << endl;
return 0;
}