题解 P5409 【【模板】第一类斯特林数·列】

Great_Influence

2019-05-19 18:43:19

Solution

特别神奇的一个思路。。。 我们考虑一个这样的式子: $$(x+1)^t$$ 我们先对它进行二项式展开,得: $$(1+x)^t=\sum_{i=0}^\infty \binom{t}{i}x^i$$ 我们将组合数拆开,有: $$(1+x)^t=\sum_{i=0}^\infty \frac{x^it^{\underline{i}}}{i!}$$ 这里出现了一个下降幂,我们运用等式展开成第一类斯特林形式: $$(1+x)^t=\sum_{i=0}^\infty\frac{x^i}{i!}\sum_{j=0}^i(-1)^{i-j}\begin{bmatrix}i\\j\end{bmatrix}t^j$$ 移项整理得: $$(1+x)^t=\sum_{i=0}^\infty t^i\sum_{j=i}^\infty\frac{(-1)^{j-i}\begin{bmatrix}j\\i\end{bmatrix}x^j}{j!}$$ 我们换一种思路展开。 $$(1+x)^t=\exp[t\ln(1+x)]$$ $$=\sum_{i=0}^\infty t^i*\frac{\ln(1+x)^i}{i!}$$ 我们将两个式子放在一起: $$\sum_{i=0}^\infty t^i\sum_{j=i}^\infty\frac{(-1)^{j-i}\begin{bmatrix}j\\i\end{bmatrix}x^j}{j!}=\sum_{i=0}^\infty t^i*\frac{\ln(1+x)^i}{i!}$$ 去除左边相同的部分,就可以得到最终式子: $$\sum_{j=i}^\infty \frac{(-1)^{j-i}\begin{bmatrix}j\\i\end{bmatrix}x^j}{j!}=\frac{\ln(1+x)^i}{i!}$$ 运用多项式 $\ln$ 和 $\exp$ 即可做到 $O(n\log n)$ 。 代码: ```cpp #include<cstdio> #include<cstdlib> #include<cctype> #include<cstring> #include<algorithm> #include<cmath> #include<cassert> #include<iostream> #define Rep(i,a,b) for(register int i=(a);i<=(b);++i) #define Repe(i,a,b) for(register int i=(a);i>=(b);--i) #define rep(i,a,b) for(register int i=(a);i<(b);++i) #define pb push_back #define mx(a,b) (a>b?a:b) #define mn(a,b) (a<b?a:b) typedef unsigned long long uint64; typedef unsigned int uint32; typedef long long ll; using namespace std; namespace IO { const uint32 Buffsize=1<<15,Output=1<<24; static char Ch[Buffsize],*S=Ch,*T=Ch; inline char getc() { return((S==T)&&(T=(S=Ch)+fread(Ch,1,Buffsize,stdin),S==T)?0:*S++); } static char Out[Output],*nowps=Out; inline void flush(){fwrite(Out,1,nowps-Out,stdout);nowps=Out;} template<typename T>inline void read(T&x) { x=0;static char ch;T f=1; for(ch=getc();!isdigit(ch);ch=getc())if(ch=='-')f=-1; for(;isdigit(ch);ch=getc())x=x*10+(ch^48); x*=f; } template<typename T>inline void write(T x,char ch='\n') { if(!x)*nowps++='0'; if(x<0)*nowps++='-',x=-x; static uint32 sta[111],tp; for(tp=0;x;x/=10)sta[++tp]=x%10; for(;tp;*nowps++=sta[tp--]^48); *nowps++=ch; } } using namespace IO; void file() { #ifndef ONLINE_JUDGE FILE*DSD=freopen("water.in","r",stdin); FILE*CSC=freopen("water.out","w",stdout); #endif } const int MAXN=1<<19; namespace poly { const int mod=167772161,gen=3; static int g[23][MAXN],iv[MAXN]; inline int power(int u,int v) { register int sm=1; for(;v;v>>=1,u=(uint64)u*u%mod)if(v&1) sm=(uint64)sm*u%mod; return sm; } inline void predone() { Rep(i,1,21) { g[i][0]=1,g[i][1]=power(gen,(mod-1)>>i); Rep(j,2,4e5)g[i][j]=(ll)g[i][j-1]*g[i][1]%mod; } iv[1]=1; Rep(i,2,4e5)iv[i]=mod-(uint64)mod/i*iv[mod%i]%mod; } static int Len,rev[MAXN]; inline void calrev() { int II=log(Len)/log(2)-1; Rep(i,1,Len-1)rev[i]=rev[i>>1]>>1|(i&1)<<II; } inline int ad(int u,int v){return(u+=v)>=mod?u-mod:u;} inline void NTT(int*F,int typ) { Rep(i,1,Len-1)if(i<rev[i])swap(F[i],F[rev[i]]); for(register int i=2,ii=1,t=1;i<=Len;i<<=1,ii<<=1,++t) for(register int j=0;j<Len;j+=i)rep(k,0,ii) { register int tt=(uint64)*(F+j+k+ii)*g[t][k]%mod; *(F+j+k+ii)=ad(*(F+j+k),mod-tt); *(F+j+k)=ad(*(F+j+k),tt); } if(typ==-1) { reverse(F+1,F+Len); register uint64 invn=power(Len,mod-2); rep(i,0,Len)*(F+i)=invn**(F+i)%mod; } } static int X[MAXN],Y[MAXN],Iv[MAXN]; inline void mul(int *a,int *b,int *c,int lenl,int lenr) { if((ll)lenl*lenr<=100) { Rep(i,0,lenl+lenr)X[i]=0; Rep(i,0,lenl)Rep(j,0,lenr) X[i+j]=(X[i+j]+(ll)a[i]*b[j])%mod; Rep(i,0,lenl+lenr)c[i]=X[i]; return; } for(Len=2;Len<=lenl+lenr;Len<<=1); calrev(); Rep(i,0,lenl)X[i]=a[i]; Rep(i,0,lenr)Y[i]=b[i]; rep(i,lenl+1,Len)X[i]=0; rep(i,lenr+1,Len)Y[i]=0; NTT(X,1),NTT(Y,1); rep(i,0,Len)X[i]=(ll)X[i]*Y[i]%mod; NTT(X,-1); Rep(i,0,lenl+lenr)c[i]=X[i]; rep(i,lenl+lenr+1,Len)c[i]=0; } inline void Inv(int*F,int*G,int ln) { Iv[0]=power(F[0],mod-2); for(register int Ln=2;Ln>>1<=ln;Ln<<=1) { rep(i,ln+1,Ln)F[i]=0; rep(i,0,Ln)X[i]=F[i],Y[i]=0; rep(i,0,(Ln>>1))Y[i]=Iv[i]; Len=Ln,calrev(); NTT(X,1),NTT(Y,1); rep(i,0,Ln)X[i]=(uint64)X[i]*Y[i]%mod; NTT(X,-1); rep(i,0,(Ln>>1))X[i]=0; NTT(X,1); rep(i,0,Ln)X[i]=(uint64)X[i]*Y[i]%mod; NTT(X,-1); rep(i,(Ln>>1),Ln)Iv[i]=mod-X[i]; } Rep(i,0,ln)G[i]=Iv[i]; } static int ExX[MAXN],ExY[MAXN],Op[MAXN]; inline void Deriv(int*F,int*G,int ln) {Rep(i,1,ln)G[i-1]=(uint64)F[i]*i%mod;G[ln]=0;} inline void Inter(int*F,int*G,int ln) {Repe(i,ln,1)G[i]=(uint64)F[i-1]*iv[i]%mod;G[0]=0;} static int LnX[MAXN]; inline void Ln(int*F,int*G,int ln) { Deriv(F,LnX,ln),Inv(F,G,ln); for(Len=2;Len<=ln<<1;Len<<=1); rep(i,ln+1,Len)LnX[i]=G[i]=0; calrev(); NTT(LnX,1),NTT(G,1); rep(i,0,Len)G[i]=(uint64)G[i]*LnX[i]%mod; NTT(G,-1); Inter(G,G,ln); } void cdq_Exp(int*a,int*F,int l,int r) { if(l==r) { if(!l)F[l]=1; else F[l]=(ll)F[l]*iv[l]%mod; return; } int md=(l+r)>>1;cdq_Exp(a,F,l,md); for(Len=2;Len<=r-l;Len<<=1); calrev(); memset(X,0,sizeof(int)*Len); memset(Y,0,sizeof(int)*Len); memcpy(X,F+l,sizeof(int)*(md-l+1)); memcpy(Y,a,sizeof(int)*(r-l)); NTT(X,1),NTT(Y,1); rep(i,0,Len)X[i]=(ll)X[i]*Y[i]%mod; NTT(X,-1); Rep(i,md+1,r)F[i]=ad(F[i],X[i-l-1]); cdq_Exp(a,F,md+1,r); } inline void Exp(int *F,int *G,int ln) { Rep(i,1,ln)Op[i-1]=(ll)F[i]*i%mod,Op[i]=0; memset(G,0,sizeof(int)*(ln+1)); cdq_Exp(Op,G,0,ln); /*Op[0]=1; for(register int Lx=2;Lx>>1<=ln;Lx<<=1) { rep(i,Lx>>1,Lx)Op[i]=0; Ln(Op,ExX,Lx); rep(i,0,Lx>>1)ExX[i]=ad(F[i+(Lx>>1)],mod-ExX[i+(Lx>>1)]); rep(i,0,Lx>>1)ExY[i]=Op[i]; rep(i,Lx>>1,Lx)ExX[i]=ExY[i]=0; Len=Lx; calrev(); NTT(ExY,1),NTT(ExX,1); rep(i,0,Len)ExX[i]=(ll)ExX[i]*ExY[i]%mod; NTT(ExX,-1); rep(i,0,Lx>>1)Op[i+(Len>>1)]=ExX[i]; } Rep(i,0,ln)G[i]=Op[i];*/ } inline void Pow(int*F,int*G,int ln,ll k) { int lst=ln+1; Rep(i,0,ln)if(F[i]){lst=i;break;} if(ln&&(__int128)lst*k>ln) {memset(G,0,sizeof(int)*(ln+1));return;} int md=ln-k*lst,bs=F[lst],iv=power(bs,mod-2); Rep(i,lst,ln)G[i]=(ll)G[i]*iv%mod; Ln(G+lst,G,md); k%=mod; Rep(i,0,md)G[i]=(ll)G[i]*k%mod; Exp(G,G,md); bs=power(bs,k); Repe(i,md,0)G[i+lst*k]=(ll)G[i]*bs%mod; memset(G,0,sizeof(int)*(lst*k)); } } using poly::mul; using poly::power; using poly::Len; using poly::calrev; using poly::NTT; using poly::mod; using poly::predone; using poly::Inv; using poly::Inter; using poly::Deriv; using poly::Ln; using poly::Exp; using poly::Pow; using poly::ad; static int n,k,X[MAXN],fac[MAXN],inv[MAXN]; int main() { file(); read(n),read(k); if(k>n)Rep(i,0,n)write(0,' '); else { predone(); fac[0]=1; Rep(i,1,n)fac[i]=(ll)fac[i-1]*i%mod; inv[n]=power(fac[n],mod-2); Repe(i,n,1)inv[i-1]=(ll)inv[i]*i%mod; X[0]=X[1]=1; Ln(X,X,n),Pow(X,X,n,k); Rep(i,0,n)X[i]=(ll)X[i]*inv[k]%mod; Rep(i,0,n)write((ll)X[i]*fac[i]%mod*((i-k)&1?mod-1:1)%mod,' '); } flush(); return 0; } ```