题解 P5434 【【模板】有标号荒漠计数】

Great_Influence

2019-06-16 19:39:45

Solution

仙人掌计数后再套一个 $exp$ 就完事了。 仙人掌计数可以参考[这篇](https://www.luogu.org/blog/user7035/loj-161-xian-ren-zhang-ji-shuo)。 代码: ```cpp #include<bits/stdc++.h> #define Rep(i,a,b) for(register int i=(a);i<=(b);++i) #define Repe(i,a,b) for(register int i=(a);i>=(b);--i) #define rep(i,a,b) for(register int i=(a);i<(b);++i) #define pb push_back #define mx(a,b) (a>b?a:b) #define mn(a,b) (a<b?a:b) typedef unsigned long long uint64; typedef unsigned int uint32; typedef long long ll; using namespace std; namespace IO { const uint32 Buffsize=1<<15,Output=1<<24; static char Ch[Buffsize],*S=Ch,*T=Ch; inline char getc() { return((S==T)&&(T=(S=Ch)+fread(Ch,1,Buffsize,stdin),S==T)?0:*S++); } static char Out[Output],*nowps=Out; inline void flush(){fwrite(Out,1,nowps-Out,stdout);nowps=Out;} template<typename T>inline void read(T&x) { x=0;static char ch;T f=1; for(ch=getc();!isdigit(ch);ch=getc())if(ch=='-')f=-1; for(;isdigit(ch);ch=getc())x=x*10+(ch^48); x*=f; } template<typename T>inline void write(T x,char ch='\n') { if(!x)*nowps++='0'; if(x<0)*nowps++='-',x=-x; static uint32 sta[111],tp; for(tp=0;x;x/=10)sta[++tp]=x%10; for(;tp;*nowps++=sta[tp--]^48); *nowps++=ch; } } using namespace IO; void file() { FILE*DSD=freopen("a.in","r",stdin); FILE*CSC=freopen("a.out","w",stdout); } const int MAXN=1<<21; namespace poly { const int mod=998244353,gen=3; static int g[23][MAXN],iv[MAXN]; inline int power(int u,int v) { register int sm=1; for(;v;v>>=1,u=(uint64)u*u%mod)if(v&1) sm=(uint64)sm*u%mod; return sm; } inline void predone() { Rep(i,1,21) { g[i][0]=1,g[i][1]=power(gen,(mod-1)>>i); Rep(j,2,4e5)g[i][j]=(ll)g[i][j-1]*g[i][1]%mod; } iv[1]=1; Rep(i,2,4e5)iv[i]=mod-(uint64)mod/i*iv[mod%i]%mod; } static int Len,rev[MAXN]; inline void calrev() { int II=log(Len)/log(2)-1; Rep(i,1,Len-1)rev[i]=rev[i>>1]>>1|(i&1)<<II; } inline int ad(int u,int v){return(u+=v)>=mod?u-mod:u;} inline void NTT(int*F,int typ) { Rep(i,1,Len-1)if(i<rev[i])swap(*(F+i),*(F+*(rev+i))); for(register int i=2,ii=1,t=1;i<=Len;i<<=1,ii<<=1,++t) { for(register int j=0;j<Len;j+=i) { rep(k,0,ii) { register int tt=(uint64)*(F+j+k+ii)*g[t][k]%mod; *(F+j+k+ii)=ad(*(F+j+k),mod-tt); *(F+j+k)=ad(*(F+j+k),tt); } } } if(typ==-1) { reverse(F+1,F+Len); register uint64 invn=power(Len,mod-2); rep(i,0,Len)*(F+i)=invn**(F+i)%mod; } } static int X[MAXN],Y[MAXN],Iv[MAXN]; inline void mul(int *a,int *b,int *c,int lenl,int lenr) { if((ll)lenl*lenr<=300) { memset(X,0,sizeof(int)*(lenl+lenr+1)); Rep(i,0,lenl)Rep(j,0,lenr) X[i+j]=(X[i+j]+(ll)a[i]*b[j])%mod; Rep(i,0,lenl+lenr)c[i]=X[i]; return; } for(Len=2;Len<=lenl+lenr;Len<<=1); calrev(); memcpy(X,a,sizeof(int)*(lenl+1)); memcpy(Y,b,sizeof(int)*(lenr+1)); rep(i,lenl+1,Len)X[i]=0; rep(i,lenr+1,Len)Y[i]=0; NTT(X,1),NTT(Y,1); rep(i,0,Len)X[i]=(ll)X[i]*Y[i]%mod; NTT(X,-1); memcpy(c,X,sizeof(int)*(lenl+lenr+1)); rep(i,lenl+lenr+1,Len)c[i]=0; } inline void Inv(int*F,int*G,int ln) { Iv[0]=power(F[0],mod-2); for(register int Ln=2;Ln>>1<=ln;Ln<<=1) { rep(i,0,min(Ln,ln+1))X[i]=F[i]; rep(i,0,Ln)Y[i]=0; rep(i,0,(Ln>>1))Y[i]=Iv[i]; Len=Ln,calrev(); NTT(X,1),NTT(Y,1); rep(i,0,Ln)X[i]=(uint64)X[i]*Y[i]%mod; NTT(X,-1); rep(i,0,(Ln>>1))X[i]=0; NTT(X,1); rep(i,0,Ln)X[i]=(uint64)X[i]*Y[i]%mod; NTT(X,-1); rep(i,(Ln>>1),Ln)Iv[i]=mod-X[i]; } memcpy(G,Iv,sizeof(int)*(ln+1)); } static int ExX[MAXN],ExY[MAXN],Op[MAXN]; inline void Deriv(int*F,int*G,int ln) {Rep(i,1,ln)G[i-1]=(uint64)F[i]*i%mod;G[ln]=0;} inline void Inter(int*F,int*G,int ln) {Repe(i,ln,1)G[i]=(uint64)F[i-1]*iv[i]%mod;G[0]=0;} static int LnX[MAXN]; inline void Ln(int*F,int*G,int ln) { Deriv(F,LnX,ln),Inv(F,G,ln); for(Len=2;Len<=ln<<1;Len<<=1); rep(i,ln+1,Len)LnX[i]=G[i]=0; calrev(); NTT(LnX,1),NTT(G,1); rep(i,0,Len)G[i]=(uint64)G[i]*LnX[i]%mod; NTT(G,-1); Inter(G,G,ln); } inline void Exp(int *F,int *H,int *G,int ln) { int Lx=ln+1,Hf=(Lx>>1)-1; Op[Hf]=0; memcpy(Op,H,sizeof(int)*Hf); rep(i,0,Hf)Op[Hf]=(Op[Hf]+(ll)F[i+1] *(i+1)%mod*H[Hf-1-i]%mod)%mod; Op[Hf]=(ll)Op[Hf]*iv[Hf]%mod; memset(Op+(Lx>>1),0,sizeof(int)*Lx/2); Ln(Op,ExX,Lx); rep(i,0,Lx>>1)ExX[i]=ad(F[i+(Lx>>1)],mod-ExX[i+(Lx>>1)]); memcpy(ExY,Op,sizeof(int)*Lx/2); memset(ExX+(Lx>>1),0,sizeof(int)*Lx/2); memset(ExY+(Lx>>1),0,sizeof(int)*Lx/2); Len=Lx; calrev(); NTT(ExY,1),NTT(ExX,1); rep(i,0,Len)ExX[i]=(ll)ExX[i]*ExY[i]%mod; NTT(ExX,-1); memcpy(Op+Len/2,ExX,sizeof(int)*Lx/2); memcpy(G,Op,sizeof(int)*ln); } void cdq_Exp(int*a,int*F,int l,int r) { if(l==r) { if(!l)F[l]=1; else F[l]=(ll)F[l]*iv[l]%mod; return; } int md=(l+r)>>1;cdq_Exp(a,F,l,md); for(Len=2;Len<=r-l;Len<<=1); calrev(); memset(X,0,sizeof(int)*Len); memset(Y,0,sizeof(int)*Len); memcpy(X,F+l,sizeof(int)*(md-l+1)); memcpy(Y,a,sizeof(int)*(r-l)); NTT(X,1),NTT(Y,1); rep(i,0,Len)X[i]=(ll)X[i]*Y[i]%mod; NTT(X,-1); Rep(i,md+1,r)F[i]=ad(F[i],X[i-l-1]); cdq_Exp(a,F,md+1,r); } inline void EXP(int *F,int *G,int ln) { Rep(i,1,ln)Op[i-1]=(ll)F[i]*i%mod,Op[i]=0; memset(G,0,sizeof(int)*(ln+1)); cdq_Exp(Op,G,0,ln); } } using poly::mul; using poly::power; using poly::Len; using poly::calrev; using poly::NTT; using poly::mod; using poly::predone; using poly::Inv; using poly::Inter; using poly::Deriv; using poly::Ln; using poly::Exp; using poly::ad; using poly::EXP; static int F[MAXN],X[MAXN]; static int G[MAXN],H[MAXN]; void getans(int*F,int lim) { F[1]=1; static int hf; for(register int len=4;len>>1<lim;len<<=1) { hf=len>>1; rep(i,hf,len)H[i]=G[i]=0; G[0]=0; rep(i,1,hf)H[i]=mod-F[i],G[i]=ad(H[i],H[i]); G[0]=H[0]=2; Inv(G,G,len-1); Len=len,calrev(); rep(i,0,len)X[i]=F[i]; NTT(H,1),NTT(X,1); rep(i,0,len)H[i]=(ll)H[i]*X[i]%mod; NTT(H,-1); mul(H,G,H,len-2,len-1); rep(i,len,len<<1)H[i]=0; Exp(H,F+1,H,len-1); Repe(i,len-1,1)H[i]=H[i-1];H[0]=0; rep(i,0,hf)G[i]=F[i]; rep(i,hf,len)G[i]=0; G[0]=mod-1; Len=len,calrev(); NTT(G,1); rep(i,0,len)G[i]=(ll)G[i]*G[i]%mod; NTT(G,-1); Inv(G,G,hf-1); ++G[0]; rep(i,hf,len)G[i]=0; mul(G,H,G,hf-1,hf); G[0]=ad(G[0],mod-2); rep(i,hf,len)G[i]=0; Inv(G,G,hf-1); rep(i,0,len)H[i]=2ll*(H[i]+mod-F[i])%mod; Len=len,calrev(); NTT(H,1),NTT(G,1); rep(i,0,len)H[i]=(ll)H[i]*G[i]%mod; NTT(H,-1); rep(i,hf,len)F[i]=mod-H[i]; } } static int fac[MAXN],inv[MAXN]; static int a[MAXN]; inline void Chkmax(int&u,int v){u<v?u=v:0;} int main() { file(); predone(); static int _,n=0; read(n); getans(F,n); fac[0]=1,inv[1]=1; Rep(i,2,n)inv[i]=mod-(ll)mod/i*inv[mod%i]%mod; Rep(i,1,n)fac[i]=(ll)fac[i-1]*i%mod; Rep(i,1,n)F[i]=(ll)F[i]*inv[i]%mod; EXP(F,F,n); write((ll)F[n]*fac[n]%mod); flush(); return 0; } ```