AT_abc459_b [ABC459B] 459

You are given $ N $ strings $ S_1, S_2, \ldots, S_N $ consisting of lowercase English letters. Define $ N $ digits $ C_1, C_2, \ldots, C_N $ as follows: - If the first character of $ S_i $ is one of `a`, `b`, `c`, then $ C_i= $ `2` - If the first character of $ S_i $ is one of `d`, `e`, `f`, then $ C_i= $ `3` - If the first character of $ S_i $ is one of `g`, `h`, `i`, then $ C_i= $ `4` - If the first character of $ S_i $ is one of `j`, `k`, `l`, then $ C_i= $ `5` - If the first character of $ S_i $ is one of `m`, `n`, `o`, then $ C_i= $ `6` - If the first character of $ S_i $ is one of `p`, `q`, `r`, `s`, then $ C_i= $ `7` - If the first character of $ S_i $ is one of `t`, `u`, `v`, then $ C_i= $ `8` - If the first character of $ S_i $ is one of `w`, `x`, `y`, `z`, then $ C_i= $ `9` Output the string obtained by concatenating $ C_1, C_2, \ldots, C_N $ in this order.

The input is given from Standard Input in the following format: > $ N $ $ S_1 $ $ S_2 $ $ \ldots $ $ S_N $

Output the string obtained by concatenating $ C_1, C_2, \ldots, C_N $ in this order.

### Sample Explanation 1 - The first character of $ S_1= $ `algorithm` is `a`, so $ C_1= $ `2`. - The first character of $ S_2= $ `heuristic` is `h`, so $ C_2= $ `4`. Thus, output `24`, which is their concatenation. ### Constraints - $ 1 \leq N \leq 10 $ - $ N $ is an integer. - $ S_i $ is a string of length between $ 1 $ and $ 10 $ , inclusive, consisting of lowercase English letters.