CF1594A Consecutive Sum Riddle

Theofanis has a riddle for you and if you manage to solve it, he will give you a Cypriot snack halloumi for free (Cypriot cheese). You are given an integer $ n $ . You need to find two integers $ l $ and $ r $ such that $ -10^{18} \le l < r \le 10^{18} $ and $ l + (l + 1) + \ldots + (r - 1) + r = n $ .

The first line contains a single integer $ t $ ( $ 1 \le t \le 10^4 $ ) — the number of test cases. The first and only line of each test case contains a single integer $ n $ ( $ 1 \le n \le 10^{18} $ ).

For each test case, print the two integers $ l $ and $ r $ such that $ -10^{18} \le l < r \le 10^{18} $ and $ l + (l + 1) + \ldots + (r - 1) + r = n $ . It can be proven that an answer always exists. If there are multiple answers, print any.

In the first test case, $ 0 + 1 = 1 $ . In the second test case, $ (-1) + 0 + 1 + 2 = 2 $ . In the fourth test case, $ 1 + 2 + 3 = 6 $ . In the fifth test case, $ 18 + 19 + 20 + 21 + 22 = 100 $ . In the sixth test case, $ (-2) + (-1) + 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 = 25 $ .