Mark and the Online Exam

马克正在维护包括 $n$ 道判断题的在线考试。然而，他丢失了所有的正确答案。他需要在他的考生生气之前找回答案。 幸运的是，他可以使用评测系统。因此，对于每次询问，您可以输入对于每个问题的答案，评测系统会输出有几个答案是正确的。 他没有足够的时间，所以他最多可以向评测系统询问 $675$ 次。请帮助马克确定答案。 请注意，正确答案是固定的，不会改变。

Mark is administering an online exam consisting of $ n $ true-false questions. However, he has lost all answer keys. He needs a way to retrieve the answers before his client gets infuriated. Fortunately, he has access to the grading system. Thus, for each query, you can input the answers to all $ n $ questions, and the grading system will output how many of them are correct. He doesn't have much time, so he can use the grading system at most $ 675 $ times. Help Mark determine the answer keys. Note that answer keys are fixed in advance and will not change depending on your queries.

The first line of the input consists of an integer $ n $ ( $ 1\leq n\leq 1000 $ ) — the number of questions.

After reading $ n $ , you can start making queries to the grading system. For each query, print a line containing a string $ s $ of length $ n $ consisting of only letters 'T' and 'F'. - $ s_i = $ 'T' means that you answer the $ i $ -question true. - $ s_i = $ 'F' means that you answer the $ i $ -question false. After a successful query, you should read an integer $ k $ ( $ 0\leq k\leq n $ ) — the number of correct answers. If you read $ n $ , then you found the answers, and your program should not make any more queries. If your program reads $ k = -1 $ instead of the number of correct answers, it means that you either made an invalid query or exceeded the query limits. Exit immediately after receiving $ -1 $ , and you will see Wrong answer verdict. Otherwise, you can get an arbitrary verdict because your solution will continue to read from a closed stream. After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use: - fflush(stdout) or cout.flush() in C++; - System.out.flush() in Java; - flush(output) in Pascal; - stdout.flush() in Python; - see documentation for other languages. Hacks To hack, use the following format: The first line contains an integer $ n $ ( $ 1\leq n\leq 1000 $ ) — the number of questions. The second line contains a string $ s $ of length $ n $ consisting of only 'T' and 'F' — the answer key.

3

1

3

FTT

TTF

4

0

3

4

FTFF

TTTT

TFTT

The empty lines in the example are just for you to better understand the interaction process. You're not required to print them. In the first example, there are $ 3 $ questions, and the answer to each question is 'true', 'true', and 'false', respectively. - The first query, guessing the answers to be 'false', 'true', and 'true', respectively, guesses only one question — the $ 2 $ -nd question — correctly. - Then, in the second query, the program correctly guesses the answer key. The interaction ends here. In the second example, there are $ 4 $ questions, and the answer to each question is 'true', 'false', 'true', and 'true', respectively. - The first query guessed none of the questions correctly, resulting in the answer $ 0 $ . - The second query guessed the $ 1 $ -st, $ 3 $ -rd, and $ 4 $ -th question correctly, resulting in the answer $ 3 $ . - In the third query, the program correctly guesses the answer key. Then, the interaction ends.