Balance Addicts

给定一个长度为 $n$ 的序列 $a$，对于每一种将 $a$ 划分成若干个子串的方式，我们设有当前划分有 $k$ 个子串，分别描述为 $(l_1,r_1),(l_2,r_2)\dots(l_k,r_k)$，定义长度为 $k$ 的数组 $s$ 满足 $s_i=\sum\limits^{r_i}_{j=l_j}a_j$。如果 $s$ 是一个回文数组，那么我们称这一种划分方式是好的。 求 $a$ 有多少好的划分。

Given an integer sequence $ a_1, a_2, \dots, a_n $ of length $ n $ , your task is to compute the number, modulo $ 998244353 $ , of ways to partition it into several non-empty continuous subsequences such that the sums of elements in the subsequences form a balanced sequence. A sequence $ s_1, s_2, \dots, s_k $ of length $ k $ is said to be balanced, if $ s_{i} = s_{k-i+1} $ for every $ 1 \leq i \leq k $ . For example, $ [1, 2, 3, 2, 1] $ and $ [1,3,3,1] $ are balanced, but $ [1,5,15] $ is not. Formally, every partition can be described by a sequence of indexes $ i_1, i_2, \dots, i_k $ of length $ k $ with $ 1 = i_1 < i_2 < \dots < i_k \leq n $ such that 1. $ k $ is the number of non-empty continuous subsequences in the partition; 2. For every $ 1 \leq j \leq k $ , the $ j $ -th continuous subsequence starts with $ a_{i_j} $ , and ends exactly before $ a_{i_{j+1}} $ , where $ i_{k+1} = n + 1 $ . That is, the $ j $ -th subsequence is $ a_{i_j}, a_{i_j+1}, \dots, a_{i_{j+1}-1} $ . There are $ 2^{n-1} $ different partitions in total. Let $ s_1, s_2, \dots, s_k $ denote the sums of elements in the subsequences with respect to the partition $ i_1, i_2, \dots, i_k $ . Formally, for every $ 1 \leq j \leq k $ , $ $$$ s_j = \sum_{i=i_{j}}^{i_{j+1}-1} a_i = a_{i_j} + a_{i_j+1} + \dots + a_{i_{j+1}-1}. $ $ For example, the partition $ \[1\\,|\\,2,3\\,|\\,4,5,6\] $ of sequence $ \[1,2,3,4,5,6\] $ is described by the sequence $ \[1,2,4\] $ of indexes, and the sums of elements in the subsequences with respect to the partition is $ \[1,5,15\] $ .</p><p>Two partitions $ i\_1, i\_2, \\dots, i\_k $ and $ i'\_1, i'\_2, \\dots, i'\_{k'} $ (described by sequences of indexes) are considered to be different, if at least one of the following holds. </p><ul> <li> $ k \\neq k' $ , </li><li> $ i\_j \\neq i'\_j $ for some $ 1 \\leq j \\leq \\min\\left\\{ k, k' \\right\\}$$$.

Each test contains multiple test cases. The first line contains an integer $ t $ ( $ 1 \leq t \leq 10^5 $ ) — the number of test cases. The following lines contain the description of each test case. The first line of each test case contains an integer $ n $ ( $ 1 \leq n \leq 10^5 $ ), indicating the length of the sequence $ a $ . The second line of each test case contains $ n $ integers $ a_1, a_2, \dots, a_n $ ( $ 0 \leq a_i \leq 10^9 $ ), indicating the elements of the sequence $ a $ . It is guaranteed that the sum of $ n $ over all test cases does not exceed $ 10^5 $ .

For each test case, output the number of partitions with respect to which the sum of elements in each subsequence is balanced, modulo $ 998244353 $ .

6
1
1000000000
2
1 1
4
0 0 1 0
5
1 2 3 2 1
5
1 3 5 7 9
32
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

1
2
3
4
2
150994942

For the first test case, there is only one way to partition a sequence of length $ 1 $ , which is itself and is, of course, balanced. For the second test case, there are $ 2 $ ways to partition it: - The sequence $ [1, 1] $ itself, then $ s = [2] $ is balanced; - Partition into two subsequences $ [1\,|\,1] $ , then $ s = [1, 1] $ is balanced. For the third test case, there are $ 3 $ ways to partition it: - The sequence $ [0, 0, 1, 0] $ itself, then $ s = [1] $ is balanced; - $ [0 \,|\, 0, 1 \,|\, 0] $ , then $ s = [0, 1, 0] $ is balanced; - $ [0, 0 \,|\, 1 \,|\, 0] $ , then $ s = [0, 1, 0] $ is balanced. For the fourth test case, there are $ 4 $ ways to partition it: - The sequence $ [1, 2, 3, 2, 1] $ itself, then $ s = [9] $ is balanced; - $ [1, 2 \,|\, 3 \,|\, 2, 1] $ , then $ s = [3, 3, 3] $ is balanced; - $ [1 \,|\, 2, 3, 2 \,|\, 1] $ , then $ s = [1, 7, 1] $ is balanced; - $ [1 \,|\, 2 \,|\, 3 \,|\, 2 \,|\, 1] $ , then $ s = [1, 2, 3, 2, 1] $ is balanced. For the fifth test case, there are $ 2 $ ways to partition it: - The sequence $ [1, 3, 5, 7, 9] $ itself, then $ s = [25] $ is balanced; - $ [1, 3, 5 \,|\, 7 \,|\, 9] $ , then $ s = [9, 7, 9] $ is balanced. For the sixth test case, every possible partition should be counted. So the answer is $ 2^{32-1} \equiv 150994942 \pmod {998244353} $ .