CF1743E FTL

Description

Monocarp is playing a video game. In the game, he controls a spaceship and has to destroy an enemy spaceship. Monocarp has two lasers installed on his spaceship. Both lasers $ 1 $ and $ 2 $ have two values: - $ p_i $ — the power of the laser; - $ t_i $ — the reload time of the laser. When a laser is fully charged, Monocarp can either shoot it or wait for the other laser to charge and shoot both of them at the same time. An enemy spaceship has $ h $ durability and $ s $ shield capacity. When Monocarp shoots an enemy spaceship, it receives $ (P - s) $ damage (i. e. $ (P - s) $ gets subtracted from its durability), where $ P $ is the total power of the lasers that Monocarp shoots (i. e. $ p_i $ if he only shoots laser $ i $ and $ p_1 + p_2 $ if he shoots both lasers at the same time). An enemy spaceship is considered destroyed when its durability becomes $ 0 $ or lower. Initially, both lasers are zero charged. What's the lowest amount of time it can take Monocarp to destroy an enemy spaceship?

Input Format

The first line contains two integers $ p_1 $ and $ t_1 $ ( $ 2 \le p_1 \le 5000 $ ; $ 1 \le t_1 \le 10^{12} $ ) — the power and the reload time of the first laser. The second line contains two integers $ p_2 $ and $ t_2 $ ( $ 2 \le p_2 \le 5000 $ ; $ 1 \le t_2 \le 10^{12} $ ) — the power and the reload time of the second laser. The third line contains two integers $ h $ and $ s $ ( $ 1 \le h \le 5000 $ ; $ 1 \le s < \min(p_1, p_2) $ ) — the durability and the shield capacity of an enemy spaceship. Note that the last constraint implies that Monocarp will always be able to destroy an enemy spaceship.

Output Format

Print a single integer — the lowest amount of time it can take Monocarp to destroy an enemy spaceship.

Explanation/Hint

In the first example, Monocarp waits for both lasers to charge, then shoots both lasers at $ 10 $ , they deal $ (5 + 4 - 1) = 8 $ damage. Then he waits again and shoots lasers at $ 20 $ , dealing $ 8 $ more damage. In the second example, Monocarp doesn't wait for the second laser to charge. He just shoots the first laser $ 25 $ times, dealing $ (10 - 9) = 1 $ damage each time.